Question

y=1/(x^2-2)^3 diferentiation help plzzz

Answer 1

This would be chain rule do you know it?

Answer 2

expound on it
plzz

Answer 3

Chain rule if i have a function inside a function f(g(x))
The derivative of such a function would be (f'(g(x)) g'(x)
Example if you want to dufferentiaite log( x^2)
Here f(x)=logx and g(x)=x^2.
So first find f'(x)=1/x so f'(g(x))=1/x^2
g'(x)=2x. So the net derivative is f'(g(x)) g'(x)= 2x/x^2=2/x.

Answer 4

Did you understand till here?

Answer 5

kinda

Answer 6

Ok so here f(x)=1/x^3 and g(x)=x^2-2. Try to do it by yourself... Basically find f' and then replace x by g(x). Multiply whatever you got by g'

Answer 7

Did you get it?