Question

horizontal shift of:
-240sin(4θ-360)
and
4cos(1/2θ-15)-2.5
Please explain how you got those answers! Thanks :)

Answer 1

If original is y= f(x)
and final is, \[y-k = a \cdot f(x-h)\]or y = a⋅f(x−h) + k
h is horizontal shift
k is vertical shift
a is stretch/ squish

Answer 2

So in this case, -360 would be considered the horizontal shift, and it doesn't consist of a vertical shift?

Answer 3

+360 is horizontal shift from -240sin(4θ)

Answer 4

Why is it positive?

Answer 5

if f(x) becomes f(x-h)
because now f(1) is moved to f(1+h)

... anyways if θ is in degrees it does not matter because -240sin(4θ-360) will look exactly like -240sin(4θ)

Answer 6

So basically what ever h's sign is in the brackets, should be reversed?
ex: -3cos(θ-15) would be positive 15?

Answer 7

yep

Answer 8

Ahhh! Okay Thanks a lot!