Question

Let g(x)= -x^(-2) + 6x^14 + pi^7.

Find g'(0.5).

Answer 1

\[g'(x)=-(-2)x^{-2-1}+6(14)x^{14-1}+0\]
i used the power rule and the constant rule
recall:
\[(x^n)'=nx^{n-1} ; (c)'=0\]

Answer 2

Do I need to find the deriv as the first step

Answer 3

yes it ask for g'

Answer 4

what about the qoutient rule for this problem?

Answer 5

so plug in .5 into g'( )

Answer 6

we don't have a quotient

Answer 7

oh neveremind

Answer 8

I got g'(x)+ 2x^-3 +84x^13

Answer 9

what's next?

Answer 10

im stuck

Answer 11

plug in .5
and please don't post this twice
if you need help fast then post in chat

Answer 12

that is suppose to say g'(x)= not g'(x)+

Answer 13

plug 0.5 for (x)?

Answer 14

so

Answer 15

g(x)= 2(0.5)^-3+84(0.5)^13

Answer 16

that is g'(0.5)

Answer 17

ok I got 1

Answer 18

is that right?

Answer 19

no 1+42^13