Question

Find the average rate of change of f from 0 to 7pi/12.

f(x)=tan(2x)

Answer 1

(4sqrt3)/(7pi)

Answer 2

Correct?

Answer 3

\[\frac{\tan(2 \cdot \frac{ 7 \pi}{12})-\tan(2 \cdot 0)}{\frac{7 \pi }{12}-0}\]

Answer 4

let me find out by simplifying this

Answer 5

yes it is correct, since it starts at (0,0)

Answer 6

\[\frac{\tan(\frac{7 \pi}{6})}{\frac{7 \pi}{12}}\]

Answer 7

\[\frac{12}{7 \pi} \cdot \tan(\frac{ 7 \pi}{6} )\]

Answer 8

oops i was wrong
\[\tan(\frac{7\pi}{6})=\frac{1}{\sqrt{3}}\]

Answer 9

\[\frac{12}{7 \pi} \cdot \frac{\sin(\frac{7 \pi}{6})}{\cos(\frac{7 \pi}{6})}\]
\[\frac{12}{7 \pi} \cdot \frac{\sin( \pi +\frac{\pi}{6})}{\cos( \pi +\frac{\pi}{6})}\]
\[\frac{12}{ 7 \pi} \cdot \frac{\frac{-1}{2}}{\frac{-\sqrt{3}}{2}}=\frac{12}{7 \pi} \cdot \frac{1}{\sqrt{3}}\]
lol sorry i was having a find an error in my latex

Answer 10

No worries