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At x = 2, (dy)/(dx) =
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what is the formula for y
depends on what y(x) is ??
here was the first part Let y= 6 x^5 - 9. Find A, B, and C so that (dy)/(dx) = Ax^B +C
A = 30 B = 4. C =0
use power rule dy/dx = 30x^4
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\[y(x)=6x^5-9\] \[{dy(x) \over dx} =30x^4\] \[{dy(2) \over dx} =30 \times 2^4=30 \times 16=480\]
thank you very much
I was stuck
thinking about our answer to see if it makes sense, 480 is a big number , if that is our gradient at that point it is very steep but our equation for y is proportional to x^4 which gets large very quickly, so it makes sense that the slope is so steep
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