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Mathematics
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OpenStudy (anonymous):
Use the fact that the trigonometric functions are periodic to find the exact value of the expression.
sin405 degrees
tan405 degrees
csc 350
sin 9pi
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4
14 years ago
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OpenStudy (dumbcow):
sin(405) = sin(405-360) = sin(45) = sqrt2/2
14 years ago
OpenStudy (dumbcow):
tan(405) = tan(45) = 1
14 years ago
OpenStudy (anonymous):
I thought that the period for tan was 180
14 years ago
OpenStudy (dumbcow):
csc(350) = csc(-10) = -csc(10) = -1/sin(10) = -5.759
14 years ago
OpenStudy (dumbcow):
it is...so you go 2 periods but you still end up with reference angle of 45
14 years ago
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OpenStudy (anonymous):
okay gotcha!
14 years ago
OpenStudy (anonymous):
please explain the csc
14 years ago
OpenStudy (dumbcow):
350 is not quite 1 period
350 -360 = -10
trig identity: csc(-theta) = -csc(theta)
14 years ago
OpenStudy (anonymous):
how do u get this: 1/sin(10) = -5.759
14 years ago
OpenStudy (dumbcow):
the last one is identical to the first except its in radians
--> sin(9pi/4) = sqrt2/2
14 years ago
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OpenStudy (dumbcow):
oh i used a calculator...if you have to have an exact expression you have to use double and half-angle formulas
14 years ago
OpenStudy (anonymous):
list all the trig identities please
14 years ago
OpenStudy (anonymous):
sin 9pi
----
4 what about that problem?
14 years ago
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