A 512 Hz tuning fork is placed over a long tube that is submerged in a column of water. The speed of sound in the air during this experiment is 343 m/s. The tube is place at one position and resonance is heard. It is raised to a new position and resonance is heard. What is the distance between the two resonances?

Question

anonymous · Answer

There are numerous distances. Essentially, any distance equal to the wavelength of any harmonic of the 512 Hz signal will create a resonance.

anonymous · Answer

D:

anonymous · Answer

I feel so stupid i figured it out...just realized the answer was in centimeters -_-. So if anyone wants to see my answer it's

v=(wavelength)(frequency) and d = (1/2)(wavelength)

$$343 m/s \div 512s$$ = .66992 m = wavelength

.66992m(1/2) = .3349m = distance convert that to cm it's 33.5 cm 
ugh physics