Question

Vectors (Precalculus)

Answer 1

http://screensnapr.com/v/FfJoiS.png

Answer 2

a) (4,3) b) (-2,1) c) (-7,1)

Answer 3

Explain C please:) and I have a new one for you.

Answer 4

http://screensnapr.com/v/rx9TyR.png Just #29

Answer 5

2*u you get if you multiply its coordinates by 2, 2*v also and than just substract them: first coordinate of u minus first coordinate of v and second minus second and you'll get that result

Answer 6

v=(\[5/\sqrt{2},5/\sqrt{2}\])

Answer 7

How did you get that?;o

Answer 8

Nevermind i got it.

Answer 9

:D

Answer 10

No wait D:I didnt.

Answer 11

Actually forget it. I don't even need to do these problems, I've been doing the wrong ones!

Answer 12

I was wondering why I never learned any of this!

Answer 13

http://screensnapr.com/v/Hws0vK.png C of this part :D

Answer 14

first you find the unit vector (vector which length is 1) in the direction of the given vector by formula \[u _{0}=u/\left| u \right|=(3,3)/\sqrt{(3^2+3^2)}=(1/\sqrt{2},1/\sqrt{2})\] ...than your vector is \[v=5\times(1/\sqrt{2},1/\sqrt{2})=(5/\sqrt{2},5/\sqrt{2})\]

Answer 15

I must go now, I'll answer you later, good luck :D