Question

e^2x -7e^2x+12=0

there are 2 answers they want both

Answer 1

Replacing e^(2x) with y, we have: y - 7*y + 12 = 0 or y=2

Thus e^(2x) = 2

We can rewrite e^(2x) as (e^x)^2, so we know that:

e^x = +- Sqrt[2] = +-Sqrt[2^(1/2)]

Taking the log, the answers are:

x = Log[2]/2 and x= Log[2]/2 + I*Pi

(the second answer is complex)

Answer 2

webwork says that isnt the right answer

Answer 3

wolframalpha.com seems to agree with me:

http://fwd4.me/0m5L