Question

Consider the piecewise defined function f(x)=x^2+4/x+2 if x<-2
0 if x=-2
2x+3 if x>-2
Calculate f(-3)-f(-2)

Answer 1

f(-3)=(-3)^2+4/-3+2=13/-1=-13
f(-2)=0
F(-3)-f(-2)=-13-0=-13

Answer 2

f(-3)-f(-2)
for x<-2
f(x)=x^2+4/x+2
so
\[f(-3)=\frac{{(-3)}^2+4}{-3+2}\]
\[f(-3)=\frac{13}{-1}\]
\[f(-3)=-13\]
for x=-2
f(x)=0
so f(-2)=0
f(-3)-f(-2)=-13-0=-13

Answer 3

how did you guys get -13 i keep getting -5....

Answer 4

What did you get for f(-3) ?

Answer 5

-5...

Answer 6

That's your trouble. What is (-3)^2?

Answer 7

lol ohhh

Answer 8

thanks

Answer 9

yw