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Mathematics 14 Online
OpenStudy (anonymous):

Can someone help me prove a property of vectors

OpenStudy (anonymous):

Prov ethat cu is a vector in R^n

OpenStudy (anonymous):

c is a scaler and u is a vector

OpenStudy (anonymous):

imagine c is\[ai+bj\] if we multiply it in c in the end we have a vector

OpenStudy (anonymous):

ummm my prof wldnt accept that

OpenStudy (anonymous):

hence vector have dirction & magnitude so cu it has too characteristic get it? could i explain well?

OpenStudy (anonymous):

ya pretty good :D

OpenStudy (jamesj):

As \( u \in \mathbb{R}^n \) we can write \( u \) as \[ u = (x_1, x_2, ..., x_n) \] where each of the \( x_i \) are real numbers. Now by definition of scalar multiplication, \[ cu = (cx_1, cx_2, ..., cx_n) \] As each \( x_i \) is a real number as is \( c \), each component \( cx_i \) is also a real number. Hence \( cu \) is an \( n\)-tuple of real numbers and therefore a member of \( \mathbb{R}^n \).

OpenStudy (anonymous):

thnx friend

OpenStudy (anonymous):

yup that is what i was looking for :D

OpenStudy (anonymous):

Thanks guys :D I still need to prove 4 more properties so I may be back

OpenStudy (anonymous):

jamsj answer is better than mine Pippa

OpenStudy (jamesj):

Imitate the method here then. Show explicitly that the resulting quantity meets exactly the definition required. good luck.

OpenStudy (anonymous):

Thanks james I finished all the proving :D On my own which is a big feat for me. I think I am getting the hang of it

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