Question

f(x)= -√x=1
Graph the functions and describe the domain and range of each function. anybody?

Answer 1

your function has two equal signs in it.

Answer 2

f(x)= -√x+1

Answer 3

domain x >=-1
range y <= 0

Answer 4

If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is
\[[0,\infty)\]

Answer 5

^not true, x can be negative

Answer 6

Yes, but it will not yield a real number

Answer 7

I'm assuming he wants real numbers

Answer 8

x + 1 cannot be less than zero

Answer 9

Umm, how about I just post the thing that has all these on them

Answer 10

It says \[-\sqrt{x}=1\]

Answer 11

How can x be negative?

Answer 12

sqrt(x+1) not sqrt(x)

Answer 13

Oh i was going by the original post. Didn't see the updated one.

Answer 14

\[f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?\]

Answer 15

That's what I thought cinar

Answer 16

that was a typo. sorry you guys!

Answer 17

So, which is it?

Answer 18

Use parentheses

Answer 19

f(x)= -√x+1

Answer 20

so 1 is not under the square root?

Answer 21

it is. x+1 are under the square root

Answer 22

OK, use parentheses next time
\[\sqrt{x+1}>0, x>=-1\]
Domain is \[[-1,\infty)\]

Answer 23

then domain is [-1,infinite)
range is [0, infinite)

Answer 24

thank you!