Question

Will give medals

Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain.

Answer 1

these are the answers
Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64.
No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64.
Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64.
No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64.

Answer 2

x-8=0 => x=8
plug in x=8 and see if you get 0 back

Answer 3

if you get 0 back then on of the factors are x-8

Answer 4

Put x=8 in the function or in other words evaluate f(8) if it equates to zero then it is a solution

Answer 5

if not then one of the factors is not x-8

Answer 6

so whats the answer ?

Answer 7

tell me what you get for f(8)

Answer 8

\[f(8)=-2(8)^3+17(8)^2-64=?\]

Answer 9

Not not a factor

Answer 10

i think its d

Answer 11

you actually don't have to put this in a calculator to check
\[f(8)=-2(8)^3+17(8)^2-8^2=8^2(-2(8)+17-1)=8^2(-16+17-1)\]

Answer 12

is -16+17-1 zero?

Answer 13

yes

Answer 14

the answer is then x-8 is a factor of the function