Question

Need help in finding the rate of change

Answer 1

s(t) = (t - pi / t + 6 pi) ^ 1/3

Answer 2

t = 2pi

Answer 3

srry dont really know how to use the equatio button

Answer 4

average rate of change over what interval?

Answer 5

it is using derivative to find it

Answer 6

oooooooooooh ok you want the derivative evaluated at
\[2\pi\] right?

Answer 7

rate of change is \[\frac{ \Delta s}{\Delta t} = \frac{ds}{dt}\]

Answer 8

\[s(t)=\left (\frac{t-\pi}{t+6\pi}\right) ^{\frac{1}{3}}\]
yes?

Answer 9

yess

Answer 10

my teacher didnt use displacement over time...only derivatives

Answer 11

ok so derivative is
\[\frac{1}{3}\left( \frac{t-\pi}{t+6\pi}\right)^{-\frac{2}{3}}\times \frac{7\pi}{(x+6\pi)^2}\]

Answer 12

ugly enough. replace x by
\[2\pi\] see what you get

Answer 13

ahh..i dont know how to use the equations..

so it is 1/3 ( pi / 8pi ) ^ -2/3 x ( 7 pi / 8pi )^2

Answer 14

i think i get it now thx