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Chemistry 14 Online
OpenStudy (anonymous):

what is the mass in grams of 2.90x10^12 lead (Pb) in atoms ?

OpenStudy (anonymous):

\[2.90x10^12 Pb atoms(\frac{1 mole Pb}{6.022x10^23 Pb atoms})(\frac{207.2 g Pb}{1 mole Pb})=\] I don't have my calculator so i will leave it to you to do that part

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