Question

initial value problem -16cos(4t+pi), s'(0)=200, s(0)=0

Answer 1

shouldn't there be a s'(t) somewhere

Answer 2

its actually d^2s/dt^2=-16cos(4t+pi), s'(0)=200, s(0)=0

Answer 3

i am having trouble in find the initial value

Answer 4

ok so you need to integrate function to find ds/dt, then integrate again to find s(t)

Answer 5

do i need to find the constant of first inegral before integrating it again?

Answer 6

yes, thats where the s'(0)=200 comes in
plug in 0 for t and set equal to 200 to solve for contant

Answer 7

okay, thankyou so much

Answer 8

your welcome

i get s(t) = cos(4t+pi) +200t +1

Answer 9

i get s(t)=16cos(4t+pi)+200t+16...:/

Answer 10

when integrating you should be dividing coefficient by 4

--> u = 4t+pi
du = 4 dt
dt = du/4

Answer 11

oh oh oh.. i totally forgot that, i wasnt even substituting. thankyou soo much.. ur a lifesaver

Answer 12

:)

Answer 13

:D