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OpenStudy (anonymous):
How do I simplify: ^3√16 + ^3√54? The answer has to be 5^3√2... how?
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OpenStudy (anonymous):
\[\sqrt[3]{16} + \sqrt[3]{54}\]
OpenStudy (anonymous):
cuberoot(16)+cuberoot(54)
=2*cuberoot(2)+3*cuberoot(2)
=5*cuberoot(2)
OpenStudy (dumbcow):
factor out perfect cubes
16 = 8*2
cube root of 8 is 2
OpenStudy (anonymous):
factor? cube root?
OpenStudy (anonymous):
cuberoot(16)=cuberoot(2)*cuberoot(8)
=cuberoot(2)*2
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OpenStudy (anonymous):
I'm still kind of confused about ^3√54...
OpenStudy (anonymous):
cuberoot(54)=cuberoot(2)*cuberoot(27)
=cuberoot(2)*3
OpenStudy (anonymous):
ohh.. how do I calculate a cuberoot?
OpenStudy (anonymous):
there are ways to approximate it,
but lets say you are trying to find cuberoot(y)
just find a number x which satisfies x*x*x=y
OpenStudy (anonymous):
ohhh... so how about ^3√54? √2 x 27 = 54, and it's going to be 2*3^3?
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OpenStudy (anonymous):
cuberoot is a number to the exponent 1/3
so ^3√54
=(54)^(1/3)
=(2*27)^(1/3)
=(2*3^3)^(1/3)
=[(2)^(1/3)]*[(3^3)*(1/3)]
=[(2)^(1/3)]*3
=3* ^3√2
OpenStudy (anonymous):
=[(2)^(1/3)]*[(3^3)*(1/3)] - I don't do to the power of 1/3 for [(3^3)?
OpenStudy (anonymous):
27=3*3*3=3^3
cuberoot(27)=cuberoot(3^3)=(3^3)^(1/3)=3
OpenStudy (anonymous):
ohhh, okay. thank you!
OpenStudy (anonymous):
np
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