If the density of gasoline is 0.66g/mL,how many kilocalories of energy are obtained from 2.8gal of gasoline?
When 1.0g of gasoline burns, 11 500kcal of energy are given off.

Question

If the density of gasoline is 0.66g/mL,how many kilocalories of energy are obtained from 2.8gal of gasoline?
When 1.0g of gasoline burns, 11 500kcal of energy are given off.

xishem · Answer

$$2.8gal(gasoline)*\frac{3.79L}{1gal}*\frac{1000mL}{1L}=10612mL(gas)$$$$D=\frac{m}{V} \rightarrow m=DV$$$$m=(0.66g*mL^{-1})(10612mL)=7003.92g(gas)$$$$7003.92g(gas)*\frac{11,500kcal}{1.0g(gas)}=80,545,080kcal$$We need to report it to 2SFs...$$8.1*10^7kcal$$

anonymous · Answer

omg thanks sooo much