Question

the limit of (1-cosx)/(sinx) as x approaches 0 is

Answer 1

a. 0
b. -∞
c.1
d-1

Answer 2

Well when we substitute x into the equation, we get a 0/0 form,
So therefore we can use l'hopitals rule
So, taking the derviative of the numerator and denominator serpeately,
We get lim x-> 0 sinx/cosx
when x = 0, sinx = 0, cos x = 1 => the limit is 0