f(x) = -2x-1 and h(x) = 3/x+1 what does (h*f)(2) = ??
f(x) = -2x-1 h(x) = 3/(x+1) f(2) = -2(2) - 1 = -4 - 1 = -5 h(2) = 3/(2+1) = 3/3 = 1 (h*f)(2) = h(2)*f(2) = 1*-5 = -5
f(2)=-5 h(2)=1 f(2)*h(2)=-5(1)=-5
Is that a valid way of writing f(2)*h(2) ?
* means times. It's valid for when you're using a computer or a calculator
I meant (h*f) seems like multiplying "functions" rather than their values. Do you understand what I mean?
Yes, you can also multiply the functions, but that would take longer. It's easier to evaluate f(2) and h(2) then multiply that together. Either way, you would get the same answer.
Thank you
hmmmm......i got the answer -3/4 ?? that is the answer in the book i am using.
depends on whether you want \[f\times g(x)\] or \[f\circ g(x)\] they are different
ok that makes sense b/c the question was (h o f)(2)
then \[h\circ f(2)=h(f(2))=h(-5)=\frac{3}{-5+1}=-\frac{3}{4}\]
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