Question

Why is 13 and -5 the wrong answer?

Answer 1

ill type it out if you cant see it

Answer 2

cant see it

Answer 3

where did you get the 13 from?

Answer 4

take the derivative, replace x by 1 and you should get 10 if i am not mistaken

Answer 5

For the function f(x) = 5x^2+3, find the equation of the tangent line to the graph of f at x=1. If the equation of the tangent line is written as: y=mx+b, what are m and b?
m=
b=

Answer 6

find f(1) to establish the point

and find f'(1) to establish a slope

Answer 7

then

y = mx + b

y = f'(1)x -f'(1)+f(1)

Answer 8

i got 13 by getting 10(1)+3

Answer 9

5(1)+3 = 8

Answer 10

5(1^2) not= 10

Answer 11

..... youre talking the derivative tho lol

Answer 12

derivative of 5x^2+3 is 10x
10(1) = 10

Answer 13

i am going to guess that the mistake was in taking the derivative and getting
\[y'=10x+3\] instead of the correct
\[y'=10x\]
just a guess

Answer 14

y = 10x -10+8

y = 10x -2

Answer 15

what amistre said

Answer 16

yeah my mistake was that i kept the 3 after taking the derivative

Answer 17

\[D_x[5x^2+3]=Dx[5x^2]+Dx[3]=10x + 0\]

Answer 18

thanks