Question

what is the energy in joules of one quantum of 55.4 nm reply in scientific notation

Answer 1

\[c= \lambda \nu \rightarrow \nu = \frac{c}{\lambda}\]Where...
c is the speed of light
lambda is the wavelength
nu is the frequency\[\nu = \frac{3.00*10^8m*s^{-1}}{55.4nm}*\frac{10^9nm}{1m}=5.4152*10^{15}Hz\]
\[E=h \nu\]Where...
E is the energy of the quanta
h is Planck's constant
nu is the frequency of the quanta
\[E=(6.626*10^{-34}\frac{m^2*kg}{s})(5.4152*10^{15}\frac{1}{s})\]Simplifying all the junk on the right, we end up getting...\[E=3.59*10^{-18}\frac{m^2*kg}{s^2}=3.59*10^{-18}J\]