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OpenStudy (anonymous):
Challenge:
Find the ratio of area of triangle and area of triangle formed using the lengths of the medians.
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OpenStudy (anonymous):
Sorry it is not a challenge it took me 2mins to realize the solution
Directrix (directrix):
If we're talking a single triangle, the area would be constant and the ratio 1:1.
OpenStudy (anonymous):
No
OpenStudy (anonymous):
area of the triangle of medians is three-fourths of the area of the given triangle.
OpenStudy (anonymous):
three medians of a triangle divide the triangle into six equal areas.
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OpenStudy (anonymous):
That is right aron
OpenStudy (anonymous):
However tell me how did you do it just want to check if we both used the same method
OpenStudy (anonymous):
Yep it's 3/4.
OpenStudy (anonymous):
I know a proof using vectors
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OpenStudy (anonymous):
Aha, vector would certainly make things much easy.
OpenStudy (anonymous):
It is a 3 line proof
And i discovered it myself
OpenStudy (anonymous):
Furthermore, the area of the triangle is :
\[1/3\sqrt{(2\sum u ^{2}v ^{2} - \sum u^{4})}\]
where u,v and w are the medians .
OpenStudy (anonymous):
@Aron that's a fairly complicated form.
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