Question

a!+b! = a^b

Answer 1

I can be rewritten using the gamma function as:
\[\Gamma(a+1) + \Gamma(b+1) = a^{b}\]

Answer 2

Any idea how to solve this?

Answer 3

As you might know this is my problem which I posted here http://math.stackexchange.com/questions/105923/

Answer 4

I have a feeling that the proving that only (2,2) and (2,3) are the only solutions is somewhat difficult.

Answer 5

Try using the gamma function.

Answer 6

So you have a solution Aron?

Answer 7

nic question aron

Answer 8

No,I don't have a solution but I was just wondering if I could solve it using the gamma function.

Answer 9

Dig deep into that Wikipedia page.

Answer 10

\[\Gamma (Z) = \int\limits\limits_{0}^{\infty}e^{-t}t^{z-1}dt\]

Answer 11

$$\stackrel{\circ.\circ}{\huge o}\angle\huge\lbrace\normalsize\text{I am tired, time for a nap! } $$

Answer 12

Is there a way to format text in the math formatter so it isn't italicized?

Answer 13

\text{}

Answer 14

The graph looks weird!

Answer 15

http://www.wolframalpha.com/input/?i=Solve%20a!%20%2B%20b!%20%3D%20a%5Eb&t=crmtb01

Answer 16

It looks like an alien spaceship

Answer 17

haha :D

Answer 18

yeah

Answer 19

Anyone able to solve it yet?

Answer 20

Cool graph! You guys are so funny!