A rocket is launched from ground level with an initial vertical velocity (v0) of 176 ft/s. After how many seconds will the rocket hit the ground? (Hint: h(t) = -16t2 + v0t + h0).

please explain.

Question

A rocket is launched from ground level with an initial vertical velocity (v0) of 176 ft/s. After how many seconds will the rocket hit the ground? (Hint: h(t) = -16t2 + v0t + h0). 

please explain.

anonymous · Answer

$$h_0=0$$ since the initial heigh of the rocket is 0

anonymous · Answer

$$v_0=176$$ since you are told the initial velocity.

anonymous · Answer

therefore your equation is 
$$h(t)=-16t^2+176t$$ and you want to know when this is zero, because when it hits the ground the height is 0 feet

anonymous · Answer

$$-16t^2+176t=0$$
$$-16 (t-11) t = 0$$
$$t=0,t=11$$

anonymous · Answer

so eleven seconds it will hit the ground

anonymous · Answer

thank you for explaining it!