Question

Please find my problem attached.

Answer 1

Do you know trigonometry. If so, find the altitude h of the triangle using
sin(72º)= h/6
your figure is a parallelogram (that is what those >> marks tell you), so the top side equals the bottom side. So AB has length 12. AE has length AB/3 = 4
the area of the parallelogram is h*base = h*12 (h from above)
the area of the triangle is (1/2)*h*AE= (1/2)*h*4= 2*h (h from above)
area of the shaded area = h*12 - 2*h = 10*h
so find h!

Answer 2

i got 60cm^2

Answer 3

how?

Answer 4

12*6 =area of the parallelogram
4*6*1/2= area of triangle
and I subtracted the triangle from the parallelogram

Answer 5

pretty close. Except 6 is not the height of the parallelogram.
you need the height