how many possible combinations can there be with the numbers 6,6,4,4,1?
if they were all different you would have 6! combinations, but since you cannot tell the 6s apart, nor the twos, it is \[\frac{6!}{2\times2}\]
"6,6,4,4,1" are 5 numbers isn't ?
lol
yeah i guess it is isn't it!
so if it was 42333 what would it be? whats the general formula?
what is an additional number between friends? ok i was wrong, maybe try \[\frac{5!}{2\times 2}\] if you want to actaully get the correct answer
haha :D
\[\frac{5\times 4\times 3\times 2}{2\times 2}=5\times 3\times 2=30\] (did i get that right?)
looks correct, but what is the general formula?
\[\frac{5!}{3!}\] for the second one
so that otheer one is really 2!x2! in the denominator?
yes, if you want to think of it that way. the number of ways you can permute 2 things is 2! = 2
awesome thanks so much!
yw
sorry about mis-counting
its all good... all worked out!
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