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evaluate the limit: as x-->0, sin (7x)/2x
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7/2
\[\frac{\sin(7x)}{7x} \cdot \frac{7}{2}\]
that should help let me know if you need more help
So, is it 7/2 since as x->0 lim sin(x)/(x) =1...I would just do something like lim (7/2) [sin(x)/(x)]?
yes, you could say so
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