Question

Evaluate the limit. As h-->0, lim (3+h)^2-3^2/h

Answer 1

is \[\lim_{h \rightarrow 0}\left( 3+h \right)^{2}-3^{2/h}\] ????

Answer 2

No, it's [(3+h)^2-3^2]/h...sorry.

Answer 3

\[\lim_{h \rightarrow 0}((3+h)^{2}-3^{2})/(h) = \lim_{h \rightarrow 0}(3+h-3)(3+h+3)/h\]
\[\lim_{h \rightarrow 0}h(h+6)/h = \lim_{h \rightarrow 0}h+6=6\]

Answer 4

remember \[a^{2}-b^{2} = (a+b)(a-b)\]