The difference between the length of the hypotenuse and the length of the next longest side of a right triangle is 3 cm. The difference between the lengths of the two perpendicular sides is 3 cm. Find the three side lengths.
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OpenStudy (anonymous):
I don't get it..
OpenStudy (turingtest):
call the hypotenuse length x:|dw:1329352306450:dw|use the Pythagorean theorem:\[x^2=(x-3)^2+(x-6)^2\]and solve for x.
OpenStudy (anonymous):
why is it x-3, and x-6?
OpenStudy (anonymous):
as The difference between the lengths of the two perpendicular sides is 3 cm
OpenStudy (anonymous):
So once I get: \[(x ^{2}-6x+9)(x ^{2}-12x+36)\]
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OpenStudy (anonymous):
what do I do after?
OpenStudy (anonymous):
utzz...rong u r missin +sign in between
OpenStudy (anonymous):
\[(x ^{2}-6x+9)+(x ^{2}-12x+36)=x ^{3}\]
OpenStudy (anonymous):
ohh, yup I put that now. And so I add to: 2x^2 - 18x + 45?
OpenStudy (anonymous):
imean....x^2
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OpenStudy (anonymous):
equate to x^2
OpenStudy (anonymous):
huh?
OpenStudy (anonymous):
so the equation becomes....... 2x^2 - 18x + 45=x^2
OpenStudy (anonymous):
hence
2x^2 - 18x + 45-x^2=0
OpenStudy (anonymous):
x^2 - 18x + 45?
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OpenStudy (anonymous):
x^2 - 18x + 45=0
OpenStudy (anonymous):
=> (x-3)(x-15)=0
OpenStudy (anonymous):
hence x=3 or x=15
OpenStudy (anonymous):
got it?/
OpenStudy (turingtest):
...and since x=3 will not produce a triangle we have x=15
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