Guys can you pls help me answering this prob. Evaluate lim x-2 over x^2-1 as x approaches 2?

Question

anonymous · Answer

replace x by 2, get zero

anonymous · Answer

$$\lim_{x\rightarrow 2}\frac{x-2}{x^2-1}=\frac{2-2}{2^2-1}=\frac{0}{3}=0$$

anonymous · Answer

@ Sattelite thanks for me helping me. :)

anonymous · Answer

yw
most every function given by and equation is continuous on its domain, meaning to find a limit you can simply evaluate the funtion.  you will only have more work to do the funciton is undefined at the limit point, specifically if you get 
$$\frac{0}{0}$$ when you evaluate the function

anonymous · Answer

could you help me again answering my take home quiz in calculus? I have 19 questions left unanswered. :(

anonymous · Answer

post
 i bet you will get lots of answers
better to post them one at a time

anonymous · Answer

yes i  will thank you so much :)

anonymous · Answer

2nd question: Find lim (sin2xcot4x) X->0.