Ask your own question, for FREE!
Chemistry 16 Online
OpenStudy (anonymous):

Lithium has two isotopes. Li-6 and Li-7. Li-6 mass = 6.015121amu Li-7 mass = 7.016003amu Lithium Mass = 6.94049amu What is percent abundance of Li-6? I know that there is an equation: 6.9409 = (% Abundance Li-6 * Weight of Li-6) + (% Abundance Li-7 * Weight of Li-7) I don't know how to use it.

OpenStudy (jfraser):

you have all 4 pieces, plug them in

OpenStudy (anonymous):

Okay. SO 6.9409 = % Li-6 * 6.015121 + % Li-7 * 7.016003 But this gives me two variables...

OpenStudy (anonymous):

100% is the sum of the two. 100% = Li 6 + Li 7 Li 6 = 100% Li7

OpenStudy (anonymous):

So 6.409 = %Li-6 * 6.015121 + (100% - %Li-6) * 7.016003 Confused... 100% * 7.016003 = 701.6003? That is a big number.

OpenStudy (xishem):

Well ask yourself if this statement makes sense: The percent abundance of Li-6 is 701.6%.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!