Question

Could someone explain how 4 + x^4 - 2 + (1/x^4) is equal to (x^2 + 1/(x^2))^2 please?

Answer 1

is the first part really
\[4+x^4-2\]??

Answer 2

yes, + 1/(x^4)

Answer 3

so first part is really
\[2+x^4\] and you have
\[2+x^4+\frac{1}{x^4}\]

Answer 4

then to add you have a denominator of
\[x^4\] so you need to write
\[\frac{2x^4}{x^4}+\frac{x^8}{x^4}+\frac{1}{x^4}\]
\[\frac{x^8+2x^4+1}{x^4}\]
\[\frac{(x^4+1)^2}{x^4}\] or
\[\left( \frac{x^4+1}{x^2}\right)^2\]

Answer 5

Oh! Thanks! :)