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Find y' y=sinx + (4cosx)/x
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Do I do quotient rule for the 2nd part?
yes
do u want me to show u?
Let's see if I know how
lol ok so u do it and then come back with the answer
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y'=cosx + x(-4sinx)-(4cosx)(1) y'=cosx-4sinx-4cosx y'=-3cosx - 4sinx
did I do it right?
no
I forgot x^2 under it
yes
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ok I will do it again
but otherwise it is basically correct
y'=cosx+ (-4sinx-4cosx)/x^2
umm no you it shld be -4xsinx
u included it the first time around
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you are so right y'=cosx+ (- 4xsinx-4cosx)/x^2
ok ya this is fine
you cld techinically factor out a -4
but it isnt necessary. only if u want ur answer to look a lil neater
what should my final answer look like? I am always interested in making it look neater.
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