a car of mass 1000kg travelling along a straight horizontal road accelerates uniformly from 15m/s to 25m/s in a distance of 320m. if the resistance to motion is 145N,find the driving force of the engine.

Question

ash2326 · Answer

Lianaro it'd help you more, if you post this in physics. You'd get better response there. Thanks :)

ash2326 · Answer

Nevertheless, I'm solving it for you here :)

anonymous · Answer

thnx :)... this question actually in my tutorial

ash2326 · Answer

Mass=1000 Kg
it's given car accelerates from 105 to 25 in a distance of 320 m
we know
$$v^2-u^2=2as$$
v=final velocity= 25 m/s
u=initial velocity= 15m/s
s=320
so
$$625-225=2*320*a$$
a=400/640 m/s^2
or
a=5/8m/s^2
Force= m*a
now Force due to this =100*5/8=62.5 Newtons
it's given the resistance is  145 N
so the driving force is= 145+62.5=207.5 Newtons

anonymous · Answer

tq :)