Question

if f:A->B be a function and co-domain=range then the function is onto?

Answer 1

Yes, range (f)=co-domain (f) implies surjection.

Answer 2

what ffm said

Answer 3

range is set of all b in codomain such that there is an a in A with
\[f(a)=b\] if that is equal to the codomain, then it means function is onto (surjective)

Answer 4

what sat said, in other words every element \(b \in B\) is the f-image of some element of A.

Answer 5

NOTE: If co-domain (f) \(\neq\) range (f) \( \implies\) Into function.

Answer 6

@satellite and foolformath
please help if u can.
Similar matrices represent the same linear transformation. please prove it or send me a link of its prove its urgent....

Answer 7

http://planetmath.org/encyclopedia/Similar.html

Answer 8

or look at "change of basis" here