if f:A-B be a function and co-domain=range then the function is onto?

Question

if f:A->B be a function and  co-domain=range then the function is onto?

anonymous · Answer

Yes, range (f)=co-domain (f) implies surjection.

anonymous · Answer

what ffm said

anonymous · Answer

range is set of all b in codomain such that there is an a in A with 
$$f(a)=b$$  if that is equal to the codomain, then it means function is onto (surjective)

anonymous · Answer

what sat said, in other words every element $b \in  B$ is the f-image of some element of A.

anonymous · Answer

NOTE: If co-domain (f)  $\neq$ range (f) $ \implies$ Into function.

anonymous · Answer

@satellite and foolformath
 please help if u can.
 Similar matrices represent the same linear transformation. please prove it or send me a link of its prove its urgent....

anonymous · Answer

http://planetmath.org/encyclopedia/Similar.html

anonymous · Answer

or look at "change of basis" here