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\[\frac{3+7i}{(2-5i)(1+3i)} \]
solve as in write in standard form?
first multiply out in the denominator and get \[\frac{3+7i}{17+i}\]
then multiply top and bottom by conjugate of the denominator, get \[\frac{3+7i}{17+i}\frac{17-i}{17-i}\] denominator will be \[17^2+1^2=290\] and the numerator will be whatever you get when you multiply
it is clear how to multiply the two complex numbers? because that is the basic job here
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Yes i think so.
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