how can i calculate the charge on a point q, given the net electric force and the values of 2 other charges?
you've got to show the whole question mam
You should add the given info into a diagram and/or redraw the diagram.
maybe this will help ;)
Yup. I can't really much though. I can't remember much from this,=.
Eashmore, can you do anything here?
I can do it.
We have to balance forces. We know the expression for electromagnetic force is\[F_E = k_e {q_1 q_2 \over r^2}\] First, let's find the component of the net force that acts in the x and y-directions. \[F_{x,3} = F_3 \cos(\theta)\]\[F_{y,3} = F_3 \sin(\theta)\] We note that both forces act positive in their respective directions. Since \(q_1\) is positive and located to the left of \(q_3\), \(q_3\) must be positive if the force from \(q_1\) on \(q_3\) is to be in the positive x-direction. The same thought process verifies this when relating \(q_2\) and \(q_3\). Additionally, let's note that the force from \(q_1\) acts on \(q_3\) solely in the x-direction, and \(q_2\) acts on \(q_3\) solely in the y-direction. Let's balance the forces in x and y-directions now. \[F_{x,3} = k_e {q_1 q_3 \over r^2}\]and\[F_{y,3} = k_e {q_2 q_3 \over r^2}\]
ok this makes sense so far
You should be able to rearrange the last two equations for \(q_3\). You should get the same value.
what do you mean? set them equal? or factor q3 out of the equation?
Pick one and solve it for \(q_3\). If we solved both for \(q_3\), both equations should produce the same value for \(q_3\).
Fx^2 + Fy^2 = 30.187 ^2 ? and sub both equations in for Fx and Fy
I have two unknowns in the above equations yes? so how do I solve for Q3?
factoring?
You only have one unknown: \( q_3 \). You know q1 and q2; you know r for each equation; and you know the constant \( k_e \). So you only need to solve for q3.
(Notice the r=1 m for one of the forces, and r=2m for another force)
In other words, for both of the equations .... the only variable you don't know is q3. So you can use either equation to solve for q3.
talk to me ... what's not making sense?
ok ...I'm out here of here then.
i do not know Fx or Fy I only know the sum of both..sorry having internet problems
You know \(F_x\) and \(F_y\). Take the total force as being \(F_3\), then use the trigonometric relations I gave you for \(F_x\) and \(F_y\). \[F_x = F_3 \cos(\theta) ~ {\rm and} ~ F_y = F_3 \sin(\theta)\]
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