parallel and perpendicular equations for the point (-5,-10) 2x + 5y -12 = 0

Question

amistre64 · Answer

parallel have same equation with a difference constat; perps switch up the xy coeffs and negate one; and change the constant too

amistre64 · Answer

// 2x + 5y + c = 0 ; calibrate with the given point

L  5x - 2y + c = 0 ; calibrate with given point

anonymous · Answer

so if you calculate it out as in slope intercept form, and got y=-2/5 = 12/5 perpendicular would just be 5/2+ whatever else?

anonymous · Answer

that was supposed to be + 12/5

amistre64 · Answer

looks to be a good set up yes

anonymous · Answer

thank you

amistre64 · Answer

slope is -2/5 for parallel \


slope is 5/2 for perp L

amistre64 · Answer

then ignore the 12 and use the point fo find a new constant

amistre64 · Answer

y = -2/5 x + c

-10 = -5(-2/5) + c

-10 = 2 + c

-12 = c


y = -2/5 - 12 ..... that worked out kinda cool lol

amistre64 · Answer

forgot the "x" in there tho ... bad amistre, bad!!  :)

anonymous · Answer

lol thank you:)

amistre64 · Answer

yw :)  the perp is the same concept; ad it looks like your competent enough for that one

anonymous · Answer

I know math, I just doubt myself. Whenever I get my work back it's always STUPID little mistakes