Question

can anyone help me solve for y? integral(dy/(100-y)) = integral(xdx)

Answer 1

\[\int\limits_{?}^{?}(1/100-y)= \int\limits_{?}^{?}(x*dx)\]

Answer 2

\[\int\frac{dy}{100-y}=\int xdx\]\[u=100-y\to du=-dy\]\[-\int\frac{du}{u}=\int xdx\]\[-\ln u=\frac12x^2\]\[\ln(100-y)=-\frac12x^2\]\[100-y=e^{-x^2/2}\]\[y=100-e^{-x^2/2}\]simplify if you wish...

Answer 3

ok i see thank you

Answer 4

I believe there should have been an absolute value sign around the u...which would make it + or minus e^...

Answer 5

But the rest of it looks good.

Answer 6

don't for get the c at the end.