Question

I need help please....
Find the domain of the rational function F(x)=-2(x^2-4)/3(x^2+4x+4)
I have factored them correctly but it said after I factored them I shouldn't reduce any common factors and should find the domain of the function using its factored form and that I need to state the domain in interval notation. I am lost and do not know how to work this out apparently

Answer 1

\[x^2+4x+4\neq0 \]
\[(x+2)^2\neq0\]

so the domain interval is:

Answer 2

\[x^2+4x+4\neq0 \]
\[(x+2)^2\neq0\]

so the domain interval is: \[x \in(-\infty,-2)\cup(-2,+\infty)\]

Answer 3

R-{-2}

Answer 4

Check your nos nena..

Answer 5

to check what?

Answer 6

I am not understanding...i was told to find the domain of the function using the factored form F(x)=[-2(x-2)(x+2)]/[3(x+2)(x+2)]....how do I work this out

Answer 7

Sorry my bad

Answer 8

Once factored you must use fact the Denominator cannot be zero for any real no

Answer 9

it's ok...:D kcbrosell what part you don't understand?

Answer 10

all of it I am failing this class big time...I dont understand all the factoring or how to put it into and equation and so on

Answer 11

every time you want to find the domain of the function which is given in fraction form denominator must not be equal to zero, so when you factor x^2+4x+4 you get the result I wrote.....

Answer 12

I am not understanding how you get to the result u wrote

Answer 13

well it's a basic binomial formula which you must know if you want to do some serious math in the future....

Answer 14

I got to this point x^2-4=(x-2)(x+2) & x^2+4x+4=(x^2+2)

Answer 15

you got wrong x^2+2x+4...it is (x+2)^2

Answer 16

o crud...so after I get that worked out do I have to put them into another equation