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Mathematics 7 Online
OpenStudy (anonymous):

how to graph y=f(x)+2 with this graph http://mathgraphs.com/plg5e/plg5emg01d01001.pdf

OpenStudy (phi):

add 2 to every y value

OpenStudy (phi):

you get the same curve, but slid up 2

OpenStudy (anonymous):

so it would be 2=f(x)+2?

OpenStudy (phi):

they want you to graph y= f(x)+2 that means put dots on the graph at certain points. For example, you put a dot at x= 0 y= -1+2=1 that is 2 up from where the original dot is. then connect the dots

OpenStudy (anonymous):

i see what your saying. but do i use the points given to me or do i choose my own?

OpenStudy (phi):

the instructions say use the graph of f. So you have to use f(x) that means find where the dot is for x=0 (it is at y=-1), add 2 to the y value, and plot it. that is what y= f(x)+2 means. Do it for every x where f(x) has a dot

OpenStudy (anonymous):

okay i see. thank you very much

OpenStudy (anonymous):

x is always constant correct

OpenStudy (phi):

you do not change the x, just the y value.

OpenStudy (anonymous):

okay. im doing y=-f(x) using the same graph so with (0,1) x=0 y=-(-1) ?

OpenStudy (anonymous):

correction *with (0,-1)

OpenStudy (phi):

OK, that's right. you should get a graph that slopes down

OpenStudy (anonymous):

would it not be the same as the original though

OpenStudy (phi):

how can it be the same when you are changing it? plot it and see.

OpenStudy (anonymous):

the points come out on the same line as the first equation (y=f(x)+2)

OpenStudy (phi):

what points did you get? here are the first two pair: original new 0,-1 0,1 1, 0 1,0

OpenStudy (anonymous):

i got the same thing also. i guess i am just confusing myself

OpenStudy (phi):

what did you get for the rest of the points?

OpenStudy (anonymous):

(3,-1),(4,-2) i get it now

OpenStudy (anonymous):

thank you

OpenStudy (phi):

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