Question

What are the possible rational zeros of f(x) = 2x3 – 4x2 – 7x + 14 ?

Answer 1

2x3 – 4x2 – 7x + 14 = 2x²(x-2)-7(x-2) = (x-2)(2x²-7) = 0
you can proceed...

Answer 2

just 2

Answer 3

you can also use the rational root theorem..

Answer 4

the other zeros are +-sqrt(7/2) but they're not ratonal numbers

Answer 5

possible rational roots would include all integer factors of 14 divided by all integer factors of the leading coefficient.

Answer 6

so +-14/2,+-7/2,+-7/1,+-7/1

Answer 7

that doesn't mean all are roots, it just means these are all of the possible roots.

Answer 8

oops I forgot a couple ....+-2/2, +-2/1