Question

Newport & Vernonville are 200 miles apart.
A car leaves Newport traveling towards Vernonville, and another car leaves Vernonville the same time, traveling towards newport.

The car leaving Newport averages 10mph more than other, and they meet after 1 hour 36. What are the average speeds of the car?

The car leaving Newport averages _______MPH?
The car leaving Vernonville averages _____MPH?

Answer 1

The distance that each car travels sums up to 200 miles.
distance = rate times time. I am thinkin you might could use that info.

Answer 2

Let x = distance of the Newport bound car
Let y =distance of the veronville bound car
x+y=200
We are given time t as 1 hour 36 min, which we need to convert to hour units
1 + 36/60 =1.6 hours.
Do I need to go on?

Answer 3

Mph of Newport bound car = x/1.6
mph of Vernonville bound car = y/1.6

Answer 4

Yes, so my 1st equation is 1.6x+1.6y=200
my second equation is x-y-10

Answer 5

I don't think so, lets see what robtobey has to say.

Answer 6

r t = d
Let r be speed of the slower car. Solve the following for r:\[(r+10)\frac{8}{5}+r\frac{8}{5} =200\]\[r=\frac{115}{2} \]\[r+10=\frac{135}{2} \]

Answer 7

I may have got off to a wrong startt.

Answer 8

Thanks robtobey.

Answer 9

\[\{67.5 \text{ mph},57.5\text{ mph}\} \]

Answer 10

Your welcome.

Answer 11

LynDor please note, 8/5 is the time 1.6 hr

Answer 12

As you can see I should of Let x =rate of slower car rather than distant, I also should of kept it in terms of one unknown (x+10) rate of faster car.

Answer 13

Thanks. I would never have answered it. So 67.5 is the car leaving newport?

Answer 14

Yes, the faster car is leaving Newport.

Answer 15

OK, thanks. Is there a limit of questions per day?

Answer 16

How do I give a medal?

Answer 17

I don't think there is a limit to the number of questions. To award a medal click on the "Good Answer" button. Good luck with your studies.