Question

A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N force stretch the rubber band? How much work does it take to stretch the rubber band this far?

Answer 1

hey lol i can help with this one

Answer 2

haha... sup man!

Answer 3

so if you set 1600n = (2n/.002m)x and solve you get x = 16

Answer 4

wow Benburn you are so smart ;) you should help me on mine

Answer 5

F1=2N
x1=0.02m
Look for "K" with the first variables

F2= 1600N
x2=?
K= The one you figured out previously.

That solves the first one.
W=f*d
F=1600N
d =Whatever was from the prev. question (as x)
W=?

Answer 6

AWWW

Answer 7

these things are blowing my mind... I thought I had a clue, guess not.

Answer 8

so to write an integral that uses that w = \[\int\limits_{0}^{13}100x dx\]

Answer 9

Ben, do I start with the F= -kx?

Answer 10

sorry its 0->16

Answer 11

ya ok let me start over. so you know you put in 2N to make it streach .02m right? so you can solve for k by 2N = k (.02m)-->k=2/.02-->100

Answer 12

yep.. so K=100

Answer 13

so next, if you know it takes 1600N how long is it? the equation is 1600N = (100)(x)
and if you solve for x, x = 1600/100---> x = 16m

Answer 14

make sense so far?

Answer 15

Yep, so 16 is delta

Answer 16

so

Answer 17

100x^2/2

Answer 18

ok so work is an integral of force. the equation will be 100x because that is k*distance...
w = int_{0}^{16}100x dx

Answer 19

\[\int\limits_{0}^{16}100x dx\] ---> [50x^2] from 16 to 0

Answer 20

I got 12800

Answer 21

Joules

Answer 22

ya is that right?

Answer 23

yep.

Answer 24

You are a great tutor, ben!

Answer 25

lol np. does it make sense?

Answer 26

Yeah man it did.. Thanks alot. I'm going to try #3 now.

Answer 27

haha ok sounds good send me a message on FB if you want me to try and answer on here