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if f(x)= ae^kx and f'(x)/f(x)= -5/2 then k= Help lol (Relearning calculus and basic rules :P )
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find the derivative of f(x): f'(x) = a*e^(kx)*k (Chain rule)
f'(x) = a*k*e^(kx) f'(x)/f(x) = -5/2, so a*k*e^(kx)/[a*e^(kx)] = -5/2
\[f(x)=ae ^{kx}\]\[f'(x)=ake ^{kx}\]reaplce:\[\frac{ake ^{kx}}{ae ^{kx}}=-\frac{5}{2}\]\[k=-\frac{5}{2}\]
a*e^(kx) on top and bottom cancel out, so u're left with k = -5/2
remember: \[f(x)=e ^{u} \]\[f \prime(x)=e ^{u}u \prime\]
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O.o This is so simple lol I am embarrassed I got this wrong now :(
dont forget, click good answer :D jeje
lol there you go :) Thanks for the help.
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