Question

more calculus help

Answer 1

\[\int\limits_{?}^{?}(1)/(xln(x ^{4}))\]

Answer 2

that 1/x is buggin me as a u sub.. but it's prolly integration by parts

Answer 3

start with
\[\frac{1}{x\ln(x^4)}=\frac{1}{4x\ln(x)}\] then it should be easy

Answer 4

Let u = ln(x^4)

Answer 5

Ha I think i got this one!

Answer 6

u = ln(x^4)
du = 4/x
simple u sub!

Answer 7

good. because i am clueless???

Answer 8

pull the 1/4 outside of the integral get
\[\frac{1}{4}\int \frac{dx}{x\ln(x)}\] then make
\[u=\ln(x),du=\frac{1}{x}dx\] and you are home free

Answer 9

well yea pretty much the same thing as satellite did

Answer 10

don't forget the properties of the log!

Answer 11

lol my method works too though :)

Answer 12

oookkk i got it

Answer 13

yes it will work and you will see that if
\[u=\ln(x^4)\] then
\[du=\frac{4}{x}dx\] but that is telling you that
\[\ln(x^4)=4\ln(x)\]

Answer 14

would the fianl answer be 1/4ln (ln(x))+c?

Answer 15

Final*

Answer 16

it would be, yes

Answer 17

sweet thanks again.

Answer 18

btw if you notice you will get a different answer from wolfram and if you like i can explain why

Answer 19

please do

Answer 20

here is what wolfram writes if you just type it in. you get
\[\frac{1}{4}\ln(\ln(x^4))+c\]

Answer 21

but
\[\ln(\ln(x^4))=\ln(4\ln(x))=\ln(4)+\ln(\ln(x))\] and
\[\ln(4) \] is a constant. so answers are the same, since the constant is just a constant, like the +C out at the end

Answer 22

oo ok that is simple enough thanks again