given the curve 4x^2+2xy-xy^3=3 find the values of dy/dx at the point (1,-1)

Question

bahrom7893 · Answer

implicit differentiation

anonymous · Answer

$$4x^2+2xy-xy^3=3$$
$$8x+2xy'+2y-y^3-3xy^2y'=0$$ replace x and y by the numbers you know and solve for 
$$y'$$

bahrom7893 · Answer

8x + 2 * (x * dy/dx + y) - (x * 3y^2 * dy/dx + y^3) = 0

bahrom7893 · Answer

Ughh I keep crashing for some reason... now just do whatever satellite said.

liizzyliizz · Answer

So would it be  7? I am not sure I probably messed something up. I will double check.

anonymous · Answer

now it is  arithmetic i  can try it, maybe

anonymous · Answer

$$8x+2xy'+2y-y^3-3xy^2y'=0$$
$$8+2y'-2-1-3y'=0$$

anonymous · Answer

i replaced each x by 1 and each y by -1, but i am not guarenteeing my answer

anonymous · Answer

this gives 
$$5-y'=0$$ or 
$$y'=5$$
again, i would not bet my lunch money on it, but it looks right

liizzyliizz · Answer

ohh i added the one in stead of subtracting :l ugh the dangers of negative signs lol