Question

If a, b are the solutions of (((15)/(t+6))+((t+4)/(3)))=4 compute the sum of a+b
plz show work and i would be very happy if someone were to help me/explain this problem

Answer 1

first let me see if i can read what is says

Answer 2

\[\frac{15}{t+6}+\frac{t+4}{3}=4\]??

Answer 3

yuppers

Answer 4

the sum of a+b for tht equation

Answer 5

well i don't think there is a shortcut. i think you have to find the solutions and add them

Answer 6

or at least write the quadratic equation out

Answer 7

oh damn i made a mistake!

Answer 8

\[\frac{45+(t+4)(t+6)}{3(t+6)}=4\]

Answer 9

\[45+(t+4)(t+6)=12(t+6)\]
\[t^2+10t+69=12t+72\]
\[t^2-2t-3=0\] and finally
\[(t-3)(t+1)=0\] solutions area 3 and -1

Answer 10

if you add them you get 2

Answer 11

it is also true that the sum of the solutions to
\[ax^2+bx+c=0\] is
\[-\frac{b}{a}\]so we did not actually have to solve once we got to
\[x^2-2x-3=0\]

Answer 12

thank much man appreciate it hope some good karma comes back to u one day ^^