two identical charged balls hang from the ceiling by insulated ropes equal length l=1.5m. A charged q=25*10^-6 is two identical charged balls hang from the ceiling by insulated ropes equal length l=1.5m. A charged q=25*10^-6 is applied to each ball. then the two ball hang at rest and supporting rope has an angle of 25degree respect to the vertical. what is the mass of each balls?
\[F=ma\]\[F _{e}=k _{e}(\left| q _{1} \right|\left| q _{2} \right|)/r^2\] You can set these equations equal to each other, and since the balls aren't moving, you know that the forces are in equilibrium. Using trigonometric functions separate the forces into x and y directions so that you can use substitution to solve for your unknowns. You know that there will be an acceleration downwards due to gravity and no acceleration in the x direction. You think you can solve it now?
|dw:1329595296046:dw|In the x-direction we have\[\sum F_x=F_e-T\sin\theta=k\frac{q^2}{r^2}-T\sin\theta=0\]in the y-direction we have\[\sum F_y=F_g-T\cos\theta=mg-T\cos\theta=0\]eliminate T between these two equations and solve for m (r can be found through trig)
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